Original Article
Int. J. Chem. Sci, Volume: 15( 4)

Elzaki Transform for Two Tank Mixing Problems

*Correspondence:
Naresh P, Faculty of Mathematics, Department of Science and Humanities, Sreenidhi Institute of Science and Technology, Ghatkesar, Hyderabad, Telangana, India, Tel: 9959525584; E-mail: [email protected]

Received: September 06, 2017; Accepted: October 16, 2017; Published: October 23, 2017

Citation: Naresh P, Umamaheshwar Rao R, Eswarlal T. Elzaki Transform for Two Tank Mixing Problems. Int J Chem Sci. 2017;15(4):205

Abstract

Integral transform method is a powerful method which is widely used to solve the several kinds of differential equations with initial or boundary conditions. The new integral transform method called as Elzaki transform method is useful for solving differential equations, integro-differential equations and also integral equations. This method is also useful for solving nonlinear differential equations; it also provides an effective and efficient way of solving a wide range of problems. In this paper, we have used the Elzaki transform method for solving the two tank mixing problems, which was an application of first order system of linear differential equation.

Keywords

Elzaki transform; Differential equations

Introduction

In science and engineering differential equations plays an important role. In order to solve the differential equations, the integral transforms were extensively used. The importance of an Integral Transforms is that they provide powerful operational methods for solving initial value problems. Mostly we use Laplace Transform technique for solving differential equations. Elzaki Transform is the new integral transform which is stronger than Sumudu and Laplace Transforms.

Elzaki Transform was introduced by Tarig Elzaki [1] in 2011. Elzaki Transform defined for function of exponential order, we consider function on the set A defined by equation For a given function in the set A the constant M must be a finite number, k1 and k2 may be finite or infinite.

The Elzaki transform is defined by equation

The sufficient conditions for the existence of the Elzaki transform are that f (t) for t ≥ 0 be piecewise continuous and of the exponential order otherwise Elzaki transform may (or) may not exist [2].

Experimental

Elzaki transform of some functions and for first derivate

Here we consider some standard functions and the first derivative which are mostly occurred in the problems on Newton’s law cooling; their Elzaki transforms are given below.

equation

equation

equation

Theorem (1): Let f (t) be the given function and equation

Proof: Given equation , By Definition of Elzaki Transformequation.

equation

Theorem: Let f (t) be the given function and equation

Proof: Given equation , By Definition of Elzaki Transformequation

equation

equation

Discussion

Application and analysis

Example 1: Suppose, we connected two tanks by pipes. First tank contains 100 liters of water and 40 grams of salt. And the second tank contains 200 liters of water and 60 grams of salt and if fresh water enters into first tank at 6 liters per minute and first tank drains into second tank at 6 liters per minute and of solution is pumped at the same rate from the second tank to the first. Find the salt content in each tank as a function of time.

Solution: Let us assume that the two tanks are tank-A and tank-B (Figure 1).

international-journal-chemical-sciences-Connected-tanks

Figure 1: Connected tanks.

And let x (t) be the amount of salt at any time in the tank-A and y (t) be the amount of salt at any time in the tank-B.

For Tank A we have,

equation

At the initial time t=0, x (0)=40. Similarly, for tank-B we have,

equation

At the initial time t=0, y (0)=60. Taking Elzaki Transform of Equation (1)

equation

Taking Inverse Elzaki Transform of equation of (3) we get, equation

Taking Elzaki Transform of equation (2) we have,

equation

For simplification we consider,

equation

Now Substituting (5) in (4), we get

equation

Taking Inverse Elzaki Transform on both side of above equation, we get

equation

The schematic diagram of this problem is shown below in Figure 2. The dotted curve in the graph shows the quantity of the salt content present in the tank-A and the line curve shows the quantity of the salt content present in the tank-B at any point of time.

international-journal-chemical-sciences-salt-content

Figure 2: The quantity of the salt content present in the tank-A and the line curve shows the quantity of the salt content present in the tank-B.

Example 2: We have two 100 gallon tanks. Tank-A is initially full of salt water with a salt concentration 0.5 liter/gallon. Tank-B is full of pure water. Pure water enters tank-A at 2 gal/min water exists the well mixed tank A at two gal/min and flows into tank-B. Water also exist tank-B at two gal/min and flows out of the system. Find the amount of salt in both tanks [3-5].

Solution: Let us assume that the amount of water in the pipe between the tanks is negligible. Let x (t) be the amount of salt in pounds in tank-A at time t and y (t) be the amount of salt in pounds in tank-B at time t. Thus, the concentration in tank A and tank B are x/100 and y/100 respectively (Figure 3).

international-journal-chemical-sciences-gallon-tanks

Figure 3: 100 gallon tanks.

The differential equation describing the rate of change of the amount of salt in tank-A is,

equation

Where, equation =Rate of substance entering into tank A - Rate of substance leaving tank-A

equation

From (6),

equation

Initially, the concentration of salt in tank-A=(0.5) (100)=50. i.e. at t=0, x(0)=50.

For tank-B, we have equation

equation

From the equation (7), we have

equation

Taking Elzaki transform on both sides we have,

equation

Taking inverse Elzaki transform of equation (10), we have

equation

From the equation (9), we have

equation

Taking Elzaki transform on both sides of (11) we have,

equation

Taking inverse Elzaki transform of equation (12), we get,

equation

From the schematic diagram given in the below in Figure 4 shows that the amount of salt in the tank-A exponentially decays, but in the tank-B it is increases due to the inflow of salt from the tank-A and then the amount of salt in the tank-B decreases.

international-journal-chemical-sciences-Amount-salt

Figure 4: Amount of salt in the tanks.

Example-3: Two well mixed 100 liter tanks are initially full of pure water. Water containing salt at a concentration of 30 g/liter flows into tank-A at a rate of 4 liters/min. Water flows from tank-A to tank-B at 4 liters/min. water evaporates from tank-B at 2 liters/min and flows out at 2 liters/min. Find the amount salt in both tanks as a function of time.

Solution: Assume that, x (t) and y (t) are the amount of salt in tank-A and tank-B respectively at time t measured in minutes, and x, y is in grams (Figure 5).

international-journal-chemical-sciences-Amount-salt

Figure 5: Amount of salt in both tanks as a function of time.

The equation describing the change in the amount of salt is,

In tank-A:

equation

In tank-B;

equation

Taking Elzaki Transform of (13),

equation

Taking Inverse Elzaki Transform of (15), we get,

equation

From (14) we have,

equation

Taking Elzaki Transform on both sides of above equation, we get

equation

We can write equation

equation

From equation (16) and (17), we get,

equation

Now by taking inverse Elzaki transform we get, equation

equation

In the graph bellow (Figure 6) the dotted curve in the graph shows the quantity of the salt content present in the tank-A and the line curve shows the quantity of the salt content present in the tank-B at any point of time.

international-journal-chemical-sciences-salt-content

Figure 6: Quantity of the salt content.

Example 4: There are two 100 gallon tanks both initially full of pure water. Water containing salt at a concentration of 1 ltr/gal flows into tank-A from an outside source at 1gal/min. Water flows from tank-A to Tank-B at 3 gal/min. Water evaporates from tank-B at 1 gal/min and is piped back to tank-A at 2 gal/min. Find the amount of salt in each tank as a function of time.

Solution: Let x (t) and y (t) are the amount of salt in tank-A and tank-B respectively at any time (Figure 7).

international-journal-chemical-sciences-function-time

Figure 7: Amount of salt in each tank as a function of time.

The differential equation for tank-A,

equation

At time t=0, x (0)=0. Similarly, for tank- B, we get,

equation

At time t=0, y (0)=0. Taking Elzaki Transform on (18), we get

equation

Taking Elzaki Transform on (19),

equation

Substituting equation in the equation (20), we have,

equation

equation

equation

equation

equation

equation

equation

equation

equation

equation

Now consider, equation and which can be written as,

equation

equation

Now

equation

equation

equation

equation

equation

equation

By simplifying we have A=-375 and B=3125/3, so from (24)

equation

From equations (23) and (25), we get,

equation

From equations (22) and (26), we get,

equation

From equations (21) and (27), we get,

equation

Taking inverse Elzaki transform of equation (28), we get,

equation

From the equation (18), we get equation

The schematic diagram for this problem is shown below in Figure 8, in which the dotted curve shows the quantity of the salt content present in the tank-A and the line curve shows the quantity of the salt content present in the tank-B at any point of time.

international-journal-chemical-sciences-quantity-salt

Figure 8: The quantity of the salt content present in the tank-A and the line curve shows the quantity of the salt content present in the tank-B at any point of time.

Conclusion

Elzaki Transform is one of the suitable methods to solve the problems related to two tank problems in which data is presented in the form of system of linear differential equations.

References